The number of points scored by Reuben in the first five basketball games of a season are shown below.

23, 15, 28, 19, 25

What would happen to the data distribution if Reuben scored 23, 30, 15, 22, and 26 points in his next five games?

Group of answer choices

The data distribution would become less peaked and more widely spread.

The data distribution would become less peaked and less widely spread.

The data distribution would become more peaked and more widely spread.

The data distribution would become more peaked and less widely spread.

The correct option is (D).

Step-by-step explanation:

The data for the number of points scored by Reuben in the first five basketball games of a season are:

A = {23, 15, 28, 19, 25}

And the data for the number of points scored by Reuben in the next five games is:

B = {23, 30, 15, 22, 26}

For the first data there are only 5 observations to draw conclusions about the spread of the data and the peak of the distribution curve.

But after the next five games played by Reuben, there are 10 observations to draw conclusions.

The spread of the data is dependent upon the sample size.

Larger the sample size the smaller is the spread. And hence the distribution curve will be more peaked.

And smaller the sample size the larger is the spread. And hence the distribution curve will be less peaked.

So, after the next five games the distribution of Reuben's score would become more peaked and less widely spread.

The correct option is (D).

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: