In the figure below, X Z is a diameter of circle A.
What is the arc measure of minor arc Y Z in degrees?

mYZ = 59°

Step-by-step explanation:

If XZ is a diameter is forms a semicircle with it's arc degree half of that of the circle, in other words 180°. That would mean:

m∠ ZAY + m∠ YAX = 180,

( 5w + 4 ) + ( 11w ) = 180,

11w + 5w + 4 = 180,

16w = 176,

w = 11°

Now mYZ is, in other words, m∠ ZAY, so let us solve for m∠ ZAY:

m∠ ZAY = 5w + 4,

m∠ ZAY = 5 * ( 11 ) + 4,

m∠ ZAY = 55 + 4,

m∠ ZAY = 59°,

mYZ = 59°

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

is there a graph

step-by-step explanation: