In 2018 the state of Arizona has a population of 7,123,898 this is an increase from 2010 when a population of 6,392,017 if the area of Arizona covers 113,998MI squared then what is the difference in population density between 2010 in 2018

The difference in population density between 2010 and 2018 is of 6.42 hab/MI²

Step-by-step explanation:

The population density is the number of habitants divided by the area.

Arizona:

Has an area of 113,998MI².

2010:

6,392,017 habitants, so the density was 6,392,017/113,998 = 56.07 hab/MI².

2018:

7,123,898 habitants, so the density was 7,123,898/113,998 = 62.49 hab/MI²

Difference:

62.49 - 56.07 = 6.42 hab/MI²

The difference in population density between 2010 and 2018 is of 6.42 hab/MI²

d

step-by-step explanation:

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft