How long was Anthony's family gone? Complete the explanation of how the answer can be found. To find the answer, count hour(s) from 5:05 to 6:05. Then count minutes to 6:35. Then count minutes to 6:45 and minutes to 6:51. I add them all up to get that the Anthony's family was gone hour(s) and minutes. Anthony's family went out to dinner. They left at the time shown on the clock. They returned home at 6:51 P. M.

Thus, the Anthony's family were away for  1 hour 46 minutes

Step-by-step explanation:

We are being told  that Anthony's family went out to dinner and they left at the time shown on the clock (i.e 5;05 P.M) and they returned home at 6:51 P.M.

We are to calculate how long was Anthony's family gone

We all know that:

60 seconds = 1 minute

60 minutes = 1 hour

So from  5:05 to 6:05 = 60 minutes

From 6:05 to 6:35 = 30 minutes

From 6:35 to 6:45 = 10 minutes

From 6:45 to 6:51 = 6 minutes

Therefore ; to deduce how long was Anthony's family gone; we will have to sum up the values of the minutes from the above time- frames up;

So;  (60  + 30  + 10  + 6 ) minutes

= 106 minutes

since 60 minutes = 1 hour

Then 106 minutes = 1 hour 46 minutes

Thus, the Anthony's family were away for  1 hour 46 minutes

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

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