Possible side lengths for a rectangular frame are 6 inches, 10 inches, and 12 inches
If all measurements are whole numbers, which dimensions can be used to frame a
picture that has an area between 45 and 50 square inches?
A. 6 in. by 8 in., 10 in. by 5 in., 12 in. by 4 in.
B. 6 in. by 7 in., 10 in. by 5 in., 12 in. by 4 in.
C. 6 in. by 8 in., 10 in. by 4 in., 12 in. by 4 in.
D. 6 in. by 7 in., 6 in. by 8 in., 10 in. by 5 in., 12 in. by 4 in.

A

Step-by-step explanation:

You have to times all of them to see the results. For example...

A. 48inches(6x8), 50inches(5x10), 48inches(12x4)

B. 42,50,48(42 is not within 45-50 inches so it can't be B)

C.48,40,48(40 is not within 45-50 inches so it can't be C)

D.42,48,50,48(42 is not within 45-50 inches so it can't be D)

meaning it's A

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.