HELP MATH ONE MORE AFTER THIS

58 units squared

Step-by-step explanation:

We want to find the area of the square. To do so, we need to find the hypotenuse of the right triangle because this coincides with the side length of the square.

We use the Pythagorean Theorem, which states that for a right triangle with legs a and b and hypotenuse c:

a^2 + b^2 = c^2

Here, a = 7 and b = 3, so:

7^2 + 3^2 = c^2

c^2 = 49 + 9 = 58

Now, the area of a square is: A = s^2, where s is the side length. Well, c is the side length, and we've already found what c^2 is (it's 58), so that means the area of the square is 58 units squared.

Thus, the answer is 58 units squared.

Step-by-step explanation:

Step 1:  Find the hypotenuse

Square area =

58 units squared

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6