The system of equations y = negative 3 x + 2 and y = one-half x minus 6 is shown on the graph below.

On a coordinate plane, 2 lines intersect around (2.3, negative 4.75).

What is a reasonable estimate for the solution?
(2 and one-third, negative 4 and three-fourths)
(negative 4 and three-fourths, 2 and one-third)
(2 and two-thirds, negative 4 and one-half)
(Negative 4 and one-half, 2 and two-thirds)

2 and one-third, negative 4 and three-fourths

Step-by-step explanation:

the solution is the point at which the system of equations are equal to each other, meaning where they intersect

i think it is x = 1.2

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.