If a ⊂ b, then a ∩ b = a ∪ b. always, sometimes, never

Hence, the property:

            A ∩ B = A ∪ B never hold .

We are given that set  A⊂B .

This means that set A is properly contained in set B.

i.e. A≠B

This means that there are some elements in set B which are not in set A.

Now we have to show whether the following property A∩B=A∪B

always, sometimes or never hold.

As A is a proper set of B.

This means that: A∩B=A ( Since A is a smaller set)

Also, A∪B=B  (Since B is a bigger set)

                   Hence, A∩B ≠ A∪B  (Since A≠ B)

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

but which class are u may know that first