Solve for the volume of the cylinder. Use 3.14 for . * Show all work

A.753.6 cubic meters
B. 3,768 cubic meters
C. 376.8 cubic meters
D. 4,521.6 cubic meters

Find solution of the linear equation y = 2/3x + 1/3

For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)

Triangle abc was translated 2 untits to the right and 3 units down. write the algebraic rule that describes the translation that was applied to triangle abc to create triangle a'b'c'.