The population model describing the population of antelope in an area is:
/
The maximum population sustainable in the area is 135, and the current population is 89. Find the population of antelope after each of the first ten years. Be sure to round to the nearest whole number before each calculation.
a.
101, 110, 116, 121, 125, 128, 130, 131, 132, 133
c.
89, 101, 110, 116, 121, 125, 128, 130, 131, 132
b.
135, 135, 135, 135, 135, 135, 135, 135, 135, 135
d.
121, 135, 136, 135, 135, 135, 135, 135, 135, 135

Please select the best answer from the choices provided

A
B
C
D

step-by-step explanation:

the first 5 right here the next 5 i will upload as separate question

the one that has a slope of 1/2 and is positive.

step-by-step explanation: 2 buckets 1 trip ; 4 buckets 2 trips and so on.

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺