Solve the equation 3x + 2 = 4x + 5 using algebra tiles. Which tiles need to be added to both sides to remove the smaller coefficient? 3 positive x-tiles3 negative x-tiles 4 positive x-tiles 4 negative x-tiles Which tiles need to be added to both sides to remove the constant from the right side of the equation? 2 positive unit tiles 2 negative unit tiles 5 positive unit tiles 5 negative unit tiles What is the solution? x = –3x = –1x = 3x = 7

Step-by-step explanation:

Given the expression

3x + 2 = 4x + 5

1. The smaller coefficient of x is 3

to remove the smaller coefficient

we need to add - 3x to both sides

3x +2 + (-3x) = 4x +5 (-3x)

3x + 2 - 3x = 4x + 5 - 3x

Collecting like terms we have

3x-3x+2= 4x-3x+5

2 = x+ 5

2. The constant on the right side is

5,to remove the constant from the right side of the equation we need to add - 5 to both sides

3x + 2+ (- 5) = 4x + 5 +(-5)

3x+ 2-5 =4x +5-5

3x-3 = 4x

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.