Point A is located at (2,9) and is reflected in the x-axis. What is the location of Point A'?

(2,-9)

Step-by-step explanation:

A reflection around the x-axis implies keeping the x-coordinate as it its (no change in its numerical value), while using the exact opposite of the numerical value of the y coordinate.

In our case then:

X coordinate unaltered = 2 stays as 2

Y coordinate opposite of the original value: 9 changes to "-9"

Therefore the coordinates of point A' are: (2,-9)

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i