A standard deck of playing cards has 13 cards in each of four suits: hearts, clubs, diamonds, and spades. Two cards are chosen from the deck at random. What is the probability of choosing one club and one spade?

a 1/2

b 13/204

c 13/102

d 15/102

13/102

Step-by-step explanation:

We will assume that order doesn't matter

P (club) =  number of clubs / total

                 13/52

Now we have 51 cards since we keep the card

P ( spade) =   number of spades / total

                     13/51

P(club, keep, spade) = 13/52 * 13/51 =13/204

But we also have the case of spade, club

P (spade) =  number of spade / total

                 13/52

Now we have 51 cards since we keep the card

P ( club) =   number of clubs / total

                     13/51

P(spade, keep, club) = 13/52 * 13/51 =13/204

Add the two together since it can be in either order

13/204+13/204

26/204 = 13/102

C

Step-by-step explanation:

13C1 × 13C1 / 52C2

169/1326

13/102

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation: