You roll a six sided die twice. What is the probability of landing on an even
number then a four? Record answer as a fraction in simplest form.

Step-by-step explanation:

probability of selecting an even number i first throw  = 3 /6 .

= 1/2

probability of selecting  number 4 in second  throw .

=1 /6

the probability of landing on an even  number then a four .

= 1 /2 x 1 / 6

= 1 / 12.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

answer: he is 272195

step-by-step explanation: all you have to do is multiple 3535 and 77 and it equals 272195