Mathematics, 22.05.2020 03:58 Laners0219

EASIEST QUESTIONS IN THE WORLD
100 POINTS

Focus on question 14 and 16
Topic: Multiplying and dividing fractions

EASIEST QUESTIONS IN THE WORLD 100 POINTS Focus on question 14 and 16 Topic: Multiplying and dividin

Answers: 3

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Answers

Answer from: yasarhan2

14 1/5

16. 1330 km

Step-by-step explanation:

16. The driving distance is 570 km from W to R

The driving distance from W to C is 2 1/3 times W to R

2 1/3 * 570

Change to an improper fraction

7/3 * 570

1330

The driving distance is 1330 km

14. 3/5ths are girls

1/3 of the girls walk

3/5 * 1/3 = 1/5

1/5 of the class is girls who walk

Answer from: Chatoloko231

14. 1/5

16. 1330 km

Step-by-step explanation:

14. 1/5

P(girl) = 3/5. This information is clear.

P(walk | girl) = 1/3. The | sign means "given;" given that the person is a girl, we know that there is a 1/3 chance she walks to school.

This question wants to know what proportion of the class is both a girl and walks to school; because of the use of the word and, we know this is the intersection of two events, symbolized ⋂.

The formula for intersection is P(A ⋂ B) = P(A) * P(A|B).

P(girl ⋂ walk) = P(girl) * P(walk | girl)

= 3/5 * 1/3 = 3/15 = 1/5

16. 1330 km

So let's represent these with variables.

From Winnipeg to Regina is 570 km, so WR = 570.

From Winnipeg to Calgary is 2 1/3 times WR, so WC = 2 1/3 * WR.

We can just use substitution to combine these two equations.

WC = 2 1/3 * WR

WC = 2 1/3 * 570 = 1330 km

Answer from: Quest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is

$y\leq -x+4$

similarly, check the second related equation.

$3(1)=0$

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is

$3y> x$

15 points write a system of inequalities to represent the shaded portion of the graph

Answer from: Quest

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in $\delta bea$ and $\delta dea$ ;

$ba=da$ , as these are radii of our given circle.

$ea=ea$

therefore, $\delta bea\cong \delta dea$ by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

$3x-24=x+10$