min
and max points
by the second derivative test when
posible.
Mathematics, 23.05.2020 03:58 avinashpolwah
Find the local
min
and max points
by the second derivative test when
posible.
2
- 2x
+ 3
3
b
2 + 3x
D
=
Guct Sin 30
Answers: 2
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You know the right answer?
Find the local
min
and max points
by the second derivative test when
posible.
min
and max points
by the second derivative test when
posible.
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