John lives in Massachusetts (MA). On a walk to work John saw 12 parked cars 8 of which have MA licence plates. If John selects randomly 9 of these 12 cars, what is the probability that all of the cars he selected will be with out of state plates?

0%

Step-by-step explanation:

8 out of 12 cars have MA license plates

4 out of 12 cars are without state plates.

If John selects 9 out of 12 cars randomly, at most 4 cars are without state plates and at least 5 cars have MA license plates. Therefore, the probability that all of the cars selected will be without state plates is 0% since it is not possible to select more than 4 cars without MA plates.

here is your mark brainliest

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)