Audrina brought $35.25 to the art supply store. She bought a brush, a sketchbook, and a paint set. The brush was 1 6 as much as the sketchbook, and the sketchbook cost 3 4 the cost of the paint set. Audrina had $1.50 leftover after buying these items. What was the cost of each item?

Step-by-step explanation:

Givens

Based on the given information, we can form the following equations.

Where is the brush and is the sketchbook.

Where is paint set.

Now, the sum of all three items would give $1.50 of leftover.

Replacing expressions, we have

Then, we use this value to find the other variables

Therefore, the brush cost $5.44, the sketchbook cost 10.88 and the paint set cost 14.50, approximately.

paint set costs $18

sketchbook costs $13.5

Brush costs $2.25

Step-by-step explanation:

Let x represent the cost of the paint set.

The sketchbook cost 3/4 the cost of the paint set. It means that the cost of the sketchbook is

3/4 × x = 3x/4

The brush was 1/6 as much as the sketchbook. It means that the cost of the brush is

1/6 × 3x/4 = 3x/24 = x/8

Audrina brought $35.25 to the art supply store. If Audrina had $1.50 leftover after buying these items, it means that the amount spent on the items is

35.25 - 1.5 = 33.75

Therefore,

x + 3x/4 + x/8 = 33.75

Multiplying through by 8, it becomes

8x + 6x + x = 270

15x = 270

x = 270/15

x = 18

The cost of the sketchbook is

(3 × 18)/4 = 13.5

The cost of the brush is

1/8 × 18 = 2.25

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step-by-step explanation:

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option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.