Megan creates a scale drawing of a car. The ratio of her scale drawing length to actual car

length is 3 cm: 2 m. The length of the car in her drawing is 6 cm.

Ivan draws a scale drawing of the same car. His ratio of scale drawing length to actual car

length is 2 cm :1 m.

What is the length of the car in Ivan's scale drawing?

Givens

First, we need to find the actual length of the car using Megan's ratio.

If 2 centimeters is equivalent to 1 actual meter of the car, 6 centimeters of drawing would be equal to

Therefore, the car is 4 meters long.

Now, using this information, we can find the length of the scale drawing of Ivan.

Therefore, Ivan's drawing is 8 centimeters long.

The length of the car in Ivan's scale drawing is 8 cm.

Step-by-step explanation: Megan creates a scale drawing for a car and her scale is measured as 3 cm : 2 m. One meter equals one hundred centimetres, that means the 3 centimetres used in Megan's drawing equals two hundred centimetres in actual length of the car. Hence, for every  two centimetres she draws, the actual length is times three hundred, which can be represented as follows;

Ratio = 3 : 200

If the drawing was eventually six centimetres, then the actual car length would be,

3/200 = 6/x

Where x represents the actual length of the car

3x = 6*200

x = (6*200)/3

x = 400

Therefore the actual length of the car is 400 centimetres (or 4 metres)

Ivan draws the same car using a ratio of two centimetres to one metre. With our conversion rate already given above (100 cm = 1 m), Ivan's ratio is

2 : 100

Having known the length of the actual car to be 400 centimetres, Ivan's drawing would have a scale calculated as;

2/100 = y/400

Where y represents the length of the car in Ivan's scale drawing

2*400 = 100y

(2*400)/100 = y

8 = y

Therefore the length of the car in Ivan's scale drawing is 8 centimetres

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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