Find the perimeter of the trapezoidal brick to the nearest tenth of an inch.

Step-by-step explanation:

The trapezoid is attached.

Remember, the perimeter is the sum of all sides. But, in this case, we don't know the lenght of all sides. So, we need to find them.

Notice that the missing side on the left is congruent to the vertical leg of the right triangle. So, we use the Pythagorean Theorem to find it. Also, observe that the horizontal leg of the right triangle is 6 feet long.

Now, we can sum all sides to find the perimeter

Therefore, the perimeter of the figure is 50 feet.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.