On a coordinate plane, a triangle has points A (negative 2, negative 2), B (1, negative 5), and C (negative 5, negative 5). If a translation of T2, –7(x, y) is applied to ΔABC, what are the coordinates of B'? (1, –5) (–4, –10) (–3, –12) (3, –12)

Step-by-step explanation:

The coordinates of the original triangle are

A(-2, -2), B(1, -5) and C(-5, -5).

The transformation is a translation of 2 units to the right side and 7 units downside. Applying the rule in each coordinate, we have

A'(-2+2 , -2-7) = A'(0, -9)

B'(1+2 , -5-7) = B'(3, -12)

C'(-5+2 , -5-7) = C'(-3 , -12)

Therefore, the coordinates of vertex B' are (3, -12), so the right answer is the last choice.

whats the question?

step-by-step explanation:

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c