The graph shows the height in feet of an object
above the ground t seconds after it was
launched from the ground. Which equation
Launched Object
h(c)
64
18
W
matches this graph?
Height Above Ground (ft)
32
3
Time (s)
h(t) = -16t? – 128t – 256
h(t) = -16° +64t
h(t) = -167² – 64
h(t) = -167 + 128t - 256

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine