A device in your school Lab releases gas at a rate of, which means 0.25 of a liter of gas is released every second. The density of the gas is, which means that there are 4.3 grams of the gas in one liter. Set up the calculation to find the number of seconds it will take for the device to release 154 grams of the gas.

Drag each tile to the correct location. The tiles can be used more than once.

143.26 sec

Step-by-step explanation:

Density = 4.3 g/l

Volume flow rate = 0.25 l/s

Mass flow rate = density x volume flow rate

= 4.3 x 0.25 = 1.075 g/s

This means 1.075 grams of the gas is released in 1 sec, therefore,

Time taken for leakage of 154 g of gas is

t = 154/1.075 = 143.26 sec

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq