The plot below shows the amount of time Mira spent on 555 math problems. All measurements are rounded to the nearest \dfrac14 4 1 start fraction, 1, divided by, 4, end fraction minute. If Mira had spent the same total amount of time, but spent an equal amount of time on each problem, how many minutes would each problem have taken? minutes

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

the clb she uses is a driver, so its a 2/5 chance she hits a 180-189 yard shot

step-by-step explanation: