A ramp with a one-meter distance from edge to edge reaches a height of 0.643 meters. What is the value of the acute angle?

a. 300

C. 600

b. 400

d. none of the above

Step-by-step explanation:

Given a ramp with a one-meter distance from edge to edge and reaches a height of 0.643 meters, the equivalent set up will form a right angled triangle where the length of the ramp will be the hypotenuse of the triangle and its height will be the opposite side of the triangle facing the acute angle directly.

To get the value of the acute angle, we will use the trigonometry ratio known as SOH, CAH, TOA.

Given length of ramp = hypotenuse = 1m

Height =Opposite side = 0.643m

Using SOH;

sin =

sin = 0.643/1

sin = 0.643

=sin⁻¹0.643

= 40°

The value of the acute angle is 40°

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

x = 23.78

step-by-step explanation: