The owner of a football team claims that the mean attendance at games is over 59,100, and he is therefore justified in moving the team to a city with a larger stadium.

Identify the type II error for the test.

Group of answer choices

A) Fail to reject the claim that the mean attendance is equal to 59,100, when it is actually less than 59,100.

B) Fail to reject the claim that the mean attendance is equal to 59,100, when it is actually greater than 59,100.

C) Fail to reject the claim that the mean attendance is more than 59,100, when it is actually less than 59,100.

D) Reject the claim that the mean attendance is equal to 59,100 when it is actually 59,100.

current in the circuit at time t is /, then the power delivered to the resistor is

step-by-step explanation:

i those same problems in math and dont know how to do them

part a: triangles gcb and epb

part b. sides cg and rp are parallel by definition of parallelogram.

angles cgb and e are congruent by being alternate interior angles of parallel lines cut by a transversal. angles gbc and ebp are congruent because they are vertical angles. by aa similarity, the triangles are similar.

part c. since the triangles are similar, the ratios of the lengths of corresponding sides are equal.

calculation of be:

gb/be = cb/bp

(400 ft)/be = 300/200

(400 ft)/be = 3/2

3be = 2 * 400 ft

3be = 800 ft

be = 800/3 ft

calculation of pe:

gc/pe = cb/bp

(350 ft)/pe = 300/200

(350 ft)/pe = 3/2

3pe = 2 * 350 ft

3pe = 700 ft

pe = 700/3 ft

if i'm not wrong, i would say that the third angle has (72) because the three sides of all triangles have 180 degrees and if we subtract 180 - 62 - 40 = (72) / but i'm not sure about 40 yd.