A restaurant needs to plan seating for a party of 150 people. Large tables seat 10 people and small tables seat 6. Let x represent the number of large tables and y represent the number of small tables. The expression 10A + 6B, which represents the total number of people you can seat using A large tables and B small tables, is called a linear combination. For instance, 150 people could be seated using 0 large tables and 25 small tables. Use that expression to enter an equation in standard form that models all the different combinations of tables the restaurant could use. Then identify at least one possible combination of tables other than (0, 25).

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

i can answer this if i have the answer choices

its a i did it myself

step-by-step explanation:

the value of x is 28.2