A rectangle has a length of x + 2 and a width of x-2, and
has an area of 60 square units. Find the length and width
of the rectangle.

The length is 10 units and width is 6 units.

Length = x+2

Width = x-2

Area = 60

Area = Length × Width

Therefore, (x+2)(x-2) = 60

x²-2x+2x - 4 = 60

Collect like terms

x² = 60+4.

x² = 64.

Therefore, in order to get the value of x, we'll find the square root of 64

x² = 64.

x = ✓64

x = 8

Length =  = x+2 = 8+2 = 10

Width = x-2 = 8-2 = 6

In conclusion, the length is 10 units and width is 6 units.

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L = 10, W = 6

Step-by-step explanation:

(x-2)(x+2) = 60

- = 60

= 60 + 4 = 64

x = = 8 or -8

-8 rejected

thus length is 8 + 2 = 10, width is 8-2=6

been looking for the answer havent been able to find it   but good luck with it