A block of wood weighing 18 pounds rests on an inclined plane that makes an angle of 60° with the horizontal. To the nearest pound, how much friction force is needed to prevent the block from sliding on the plane?

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10

sadsadsadsad

step-by-step explanation:

hi how are you doing today? if you ever need just tell me

step-by-step explanation:

need more info

step-by-step explanation: