Hello!
the answer is:
the lateral area is equal to ![352m^{2}](/tex.php?f=352m^{2})
![lateralsidearea=352m^{2}](/tex.php?f=lateralsidearea=352m^{2})
why?
to find the lateral area of the square pyramid, first we need to find the perimeter of the base, and then, find the lateral area using the following formulas:
![baseperimeter=4s](/tex.php?f=baseperimeter=4s)
![lateralsidearea=\frac{1}{2}baseperimeter*slantheight](/tex.php?f=lateralsidearea=\frac{1}{2}baseperimeter*slantheight)
where,
s, is the base length
slant height, is the height of a the side of the pyramid
we are given:
![s=8m\\slantheight=22m](/tex.php?f=s=8m\\slantheight=22m)
now, calculating the perimeter of the base, we have:
![baseperimeter=4s=4*8m=32m](/tex.php?f=baseperimeter=4s=4*8m=32m)
then, calculating the lateral area:
![lateralsidearea=\frac{1}{2}baseperimeter*slantheight](/tex.php?f=lateralsidearea=\frac{1}{2}baseperimeter*slantheight)
![lateralsidearea=\frac{1}{2}32*22m=352m^{2}](/tex.php?f=lateralsidearea=\frac{1}{2}32*22m=352m^{2})
hence, we have that the lateral area is equal to ![352m^{2}](/tex.php?f=352m^{2})
have a nice day!
![Find lateral area of squared pyramid](/tpl/images/04/00/MqHJ1Zsd6H3Xim2F.jpg)