Paul wants to write equations in the form y=mx+b for the lines passing through point D that are parallel and perpendicular to line h. First he finds the slopes of these two lines. What could he do next to find the y-intercepts?

Substitute the slope and the coordinate of D into the equations and solve for b for each equation

Step-by-step explanation:

The equation for a line is y = mx+b

where m is the slope and b is the y intercept

We know m

We have a point (x,y)

We can substitute into the equation and solve for b

First option

Step-by-step explanation:

In y = mx + b, m is the slope and b is the y-intercept

Plug in m, and coordinates of D and solve for b

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

where did you get them? if you picked from the grass, is is probably poisonous.

step-by-step explanation: