Helppp plzz! Four shapes are listed below.

I. Triangle
II. Parallelogram
III. Pentagon
IV. Hexagon

Which of these are possible cross sections of a cube?

A. I and II

B. I, II, and III

C. I, II, and IV

D. I, II, III, and IV

the answers D all of them

Step-by-step explanation:

When a plane intersects a cube there is a variety of shapes of the resulting cross section.

a single point (a vertex of the cube)

a line segment (an edge of the cube)

a triangle (if three adjacent faces of the cube are intersected)

a parallelogram (if two pairs of opposite faces are intersected – this includes a rhombus or rectangle)

a trapezium (if two pairs of

a pentagon (if the plane meets all but one face of the cube)

a hexagon (if the plane meets all faces of the cube)

a pentagon (if the plane meets all but one face of the cube)

a hexagon (if the plane meets all faces of the cube)

The last five of these (the non-degenerate cases)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

im not sure

step-by-step explanation: