The paper cup is 9 cm tall and the circular opening has a radius of 2.5 cm.

What is the minimum amount of paper needed to make the paper cup to the nearest whole cm² assuming no overlap in the paper?

181cm^2

Step-by-step explanation:

The minimum amount of paper needed to make the cup to the nearest whole number will be = to the surface area of the cylinder = A=2πrh+2πr2.

Where π= 22/7, r = 2.5cm, h = 9cm

A = 2×22/7×2.5×9+2×22/7×2.5×2.5

A= 141.428+39.285

A= 180.713

A = 181cm^2

the correct answer is 5

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length