Which function has the same range as fx)=-2 VX-3 +8?
g(x)=√x-3-8
g(x)=√x-3+8
g(x)=-x+3+8
g(x)=√x-3-8

First lets find the range of -2 sqrt(x - 3) + 8

x cannot be < 3   or f(x) would not be real  

when x = 3 f(x) = 8 

and for all other values of x  f(x) will tend to  - infinity

range is [8, - infinity)

if we do same for the 4 choices we'll see that  - sqrt(x - 3)+8  will have same range

or this:     answer is:

g(x)=-\sqrt{x+3}+8    Step-by-step explanation:

we have

f(x)=-2\sqrt{x-3}+8 using a graphing tool

see the attached figure N

The domain is the interval > [3, ∞)

The range is the interval > (-∞, 8]

Verify the range of each case by graphing tool

see the attached figure N using a graphing tool

see the attached figure N

The domain is the interval > [3, ∞)

The range is the interval > (-∞, 8]

Verify the range of each case by graphing tool

see the attached figure N 2 case A) g(x)=\sqrt{x-3}-8 The range is the interval > [-8,∞) case B) g(x)=\sqrt{x-3}+8 The range is the interval > [8,∞) case C) g(x)=-\sqrt{x+3}+8

The range is the interval >(-∞, 8] > is the solution (same range that f(x))  case D) g(x)=-\sqrt{x-3}-8

The range is the interval > (-∞, -8]

10000

step-by-step explanation: divide by 2,

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation: