Which points are on the graph of the equation 3-6x+2y=-5

Step-by-step explanation:

Y - intercept = (0 , -4)

X - intercept = (4/3 , 0)

You only need these two points and then you get a linear function.

First to find y-intercept, the (x) value has to be 0. So substitute 0 for (x).

You get 3-6(0)+2y=-5

now solve that. you get 3-0+2y=-5

= 3+2y=-5

= 2y = -8

= y = -4

Knowing that y = -4, x = 0. You have a point now. (0 , -4 )

Do the same for x - intercept, but this time (y) = 0. So you would get

3 - 6x + 2(0) = -5

= 3 - 6x + 0 = -5

= 3 - 6x = -5

= -6x = -8

= x = 8/6

which is app = to 4/3

hope this is what you were asking for!

step-by-step explanation:

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step-by-step explanation: