Find m angle d for m angle b = 65
The figure is not drawn to scale

Denote O as center of circle, draw OA, OC.

As property of tangent line from outside of circle (angle OAD = angle OCD = 90 deg):

=> AOC + D = 180

Moreover, angle  AOC = 2 x angle B = 2 x 65 = 130

=> D = 180 - 130 = 50 deg

Hope this helps!

:)

50°

Step-by-step explanation:

Angle of arc AC = 2 × 65 = 130

(Angle at the centre is twice the angle on the circumference)

Tital angle of the quadrilateral with one vertex at the centre = 360

m(D) + 90 + 90 + 130 = 360

m(D) = 360 - 310 = 50°

x = 12

y = 1

for the points!