Solve the quadratic equation. x2+2x−8=0

x=2 x=-4

Step-by-step explanation:

x2+2x−8=0

Step 1: Factor left side of equation.

(x−2)(x+4)=0

Step 2: Set factors equal to 0.

x−2=0 or x+4=0

x=2 or x=−4

x=2 or x=−4

x=2 or x=-4

Step-by-step explanation:

ax^2+bx+c=0

when solving this equation you should find two numbers that if we multiply them we get c and when we subtract them we get b so in this equation we get 2 and -4

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}