Please help ASAP this is very important I will mark brainliest

Part A: Option D,

Part B: Option C

Step-by-step explanation:

~ Part A ~

In this question we can use process of elimination:

1. The first requirement is that the quadrilateral has one pair of parallel sides. Each of the following shapes, rectangles, square, parallelogram etc. by definition has 2 parallel sides ⇒ all but a trapezoid. This is as a parallelogram is defined to be a shape with 2 pairs of parallel sides, and squares, rectangles and rhombus are reconized as a parallelogram ( but not vise versa).

2. To further prove that this shape is indeed a trapezoid, it says that the lengths of these parallel sides are 1 3/4ths and 1 1/4ths. Respectfully in each figure ( but the trapezoid again ) opposite sides are congruent, provided each figure but a trapezoid is a parallelogram, and one of it's criterias is that opposite sides ≅

3. Two angles that measure 36 degrees. Well in the first two figures being a square and rectangle, they contain only 90 degree angles, so that it not a possibility. The second and third figures are the only possible ones, as in a parallelogram opposite angles ≅ and in a isoceles trapezoid base angles ≅

4. As a parallelogram doesn't meet that first two criteria for this shape, this shape must be a trapezoid, or option D

~ Part B ~

As provided in the previous question, this quadrilateral of a shape is a trapezoid...( Option C )

answer: x

step-by-step explanation:

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step-by-step explanation: