Which is an equation of the line thruogh (-1,-4) and parallel to the line 3x+y=5

y = -3x-7

Step-by-step explanation:

3x+y=5

First put this in slope intercept form

Subtract 3x from each side

3x-3x+y=-3x+5

y = -3x+5

The slope is -3 and the y intercept is 5

Parallel lines have the same slope so our new line will have a slope of -3

It goes through the point (-1,-4)

Using slope intercept form

u = mx+b

y = -3x+b

Substituting the point into the equation to solve for b

-4 = -3(-1) +b

-4 = 3+b

-4-3 = b

b = -7

Using the slope and the y intercept

The line is y = -3x-7

y = -3x - 7

Step-by-step explanation:

3x + y = 5

y = -3x + 5

Parallel lines have the same slope, so m = -3

y - -4 = -3(x - -1)

y + 4 = -3(x + 1)

y + 4 = -3x - 3

y = -3x - 7

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

me! what did you put for this question?

step-by-step explanation: