Given
\qquad m \angle ABDm∠ABDm, angle, A, B, D is a straight angle.
\qquad m \angle CBD = 8x + 16^\circm∠CBD=8x+16
∘
m, angle, C, B, D, equals, 8, x, plus, 16, degrees
\qquad m \angle ABC = 6x - 60^\circm∠ABC=6x−60
∘
m, angle, A, B, C, equals, 6, x, minus, 60, degrees
Find m\angle ABCm∠ABCm, angle, A, B, C: