The probability of rolling a 3 with a single six-sided die is 1/6. The probability of rolling
a 5 on a single six-sided die is 1/6. Thus the probability of rolling a 3 and then a 5 on
back to back rolls of a six-sided die is 1/6 x 1/6 = 36.

We can perform this calculation
because rolling a 3 and then a 5 are known as a event?
Find the blank answer!

where is the figure

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

42.4 6th grade students prefer hip hop

step-by-step explanation:

40 percent of 106 = 42.4