Jeanette wants save money, but she has not been good at it in the past. the ratio of the amount of money in jeanette's saving account to the amount of money in her checking account was 1: 6. because jeanette is trying to get better at saving money, she moves some money out of her checking account and into her saving account. now, the ratio of the amount of money in her savings account to the amount of money in her checking account is 4: 3. if jeanette had 936 dl in her checking account before moving money, how much money does jeanette have in each account after moving money ?

Hello there!

The things that we know are:

Before, The ratio of the amount of money in Jeanette's saving account to the amount of money in her checking account, and now is 4:3.

We also know that before, she had $963 in her checking account.

because before the ratio was 1:6, this means that she also had a sixth of that amount in her saving account, or: (1/6)*$963 = $160.50 in her saving account.

This adds to a total of: $963 + $160.50 = $1123.50

now we know that the ratio is 4:3, if we call x to the amount that she has in her saving acount, and y to the amount that she has in her checking acount, then, this ratio says:

4y = 3x

we also know that x + y = total amount of money = $1123.50

so we can isolate y in this second equation: y = ($1123.50 - x) and replace it in the first equation:

4y = 3x

4*($1123.50 - x) = 3x

-4x + $4494 = 3x

7x = $4494

x = $4494/7 = $642

So she has 642 dollars in her saving acount, and as we know;

y + $642 = $1123.50

y = $1123.50 - $642 = $481.50

So she has 481.50 dollars in her checking account.

24

step-by-step explanation:

if it takes 8 pounds to make 12 divide 12 by 8 and you get 1.5, 1.5 x 16 = 24

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source