Please help 75 points and Branliest PLease help

A figure is located at (0, 0), (−3, −4), and (−3, 0) on a coordinate plane. What kind of 3-D shape would be created if the figure was rotated around the x-axis? Provide an explanation and proof of your answer to receive full credit. Include the dimensions of the 3-D shape in your explanation.

to obtain 3d figure,you need to turn the point-3,4 around a circle each 90° . it should land on -3,0,4 -3,4,0... and -3,0,-4. this will make the shape a circular cone

Step-by-step explanation:

I hope this helped.

A figure is located at A(0, 0), B(−3, −4), and C(−3, 0) on a coordinate plane.

This form a right triangle ( because vector AC(3, 0) is perpendicular with vector BC(0, 4) at C. You can check it by take multiplication of vector AC and BC, you would get: vector AC x vector BC = 3 x 0 + 0 x 4 = 0)

And as you know a cone is created by rotating a right triangle around its side (not hypotenuse). Here, the right triangle ABC has AB as hypotenuse and AB is not lying on rotating axis (x axis).

=> The 3D-shape, which is created by rotating ABC around x-axis would be a cone.

Hope this helps!

:)

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1