Can you help me please
Find the distance between the points (1,1) and (7,-7)

10 units

Step-by-step explanation:

to find the distance between two points you will need to use the distance formula:

the x1 refers to the x coordinate in the first bracket, the x2 refers to the x coordinate in the second bracket, etc.

insert the coordinates into the equation:

a double negative equals a positive

insert this equation into your calculator:

= 10

∴ the distance between the points (1,1) and (7,-7) are 10 units

I hope this was helpful :-)

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

1. 2

2. 11

3. 5

4. 6

5. 7

6. 5

7. -1

8. 1

step-by-step explanation: