Prove two triangles congruent by a side, a median drawn to that side, and the angle formed by the side and the median.

Let's call one triangle ABC, and M the midpoint of AB.

Let's call the other triangle DEF, and midpoint N of DE.

We have a congruent side, AB=DE, congruent medians CM=FN, and congruent angles, ∠AMC=∠DNF

AB ≅ DE  Given

AM ≅ BM and DN ≅ EN    Def median/midpoint

AM+BM=AB  and DN+EN=DE     Segment addition theorem

2AM=2BM=AB and 2DN=2EN=DE   Substitution (eg BM for AM)

AM ≅ BM ≅ DN ≅ EN        Transitivity, algebra

CM ≅ FN   Given

∠AMC ≅ ∠DNF   Given

ΔAMC ≅ ΔDNF     Side Angle Side

AC ≅  DF   CPCTC

∠BMC ≅ ∠ENF   Supplements of congruent angles are congruent

ΔBMC ≅ ΔENF     Side Angle Side

BC ≅  EF      CPCTC

Δ ABC ≅ Δ DEF   Side Side Side

x is greater than 5

step-by-step explanation:

2x+7 is greater than 17

    -7                           -7

2x is greater than 10

divide by 2 each side

x is greater than 5

where is the diagram? shown below where? ?

step-by-step explanation: