Paul baked 208 brown loaves. if the ratio of white loaves to brown loaves is 3:2, how many loaves did he bake in total

520 loaves

Step-by-step explanation:

First, let's find how many white loaves he baked.

Let's make a proportion.

white loaves/brown loaves= white loaves/brown loaves

He baked 3 white loaves for every 2 brown loaves. He baked x white loaves for 208 brown loaves.

3/2=x/208

Now, we have to solve for x. To do this, we have to get x by itself. x is being divided by 208. To reverse this, multiply both sides by 208

208*3/2=x/208*208

208*3/2=x

312=x

He baked 312 white loaves.

Now, we have to find the total number of loaves he baked.

To do this, add the brown loaves and the white loaves.

brown loaves+white loaves

He baked 208 brown loaves and 312 white loaves

208+312

520

He baked 520 loaves in total

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

heudhduxhdnshenebdutbbt

step-by-step explanation:

hrhhdhdbbrurb ees