If a = 150 inches, b = 50 inches, and C = 120º find c.
Round to the nearest tenth of an inch.

180.3

Step-by-step explanation:

a=150

b=50

C=120

c^2=a^2+b^2-2 x a x b x cosC

c^2=150^2+50^2-2x150x50xcos120

c^2=150x150+50x50-2x150x50xcos120

c^2=22500+2500-15000cos120

c^2=25000-15000x-0.5

c^2=25000+7500

c^2=32500

c=√(32500)

c=180.3

180.3 inches

Step-by-step explanation:

Using cosine law:

c² = 150² + 50² - 1(150)(50)cos(120)

c² = 32500

c = 50sqrt(13)

c = 180.3 (nearest tenth)

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it