Mathematics, 17.05.2020 04:57 angelteddy033
A certain circle can be represented by the following equation. x^2+y^2+8x-16y+31=0x 2 +y 2 +8x−16y+31=0x, squared, plus, y, squared, plus, 8, x, minus, 16, y, plus, 31, equals, 0 What is the center of this circle ? ((left parenthesis ,,comma ))right parenthesis What is the radius of this circle ? units
Answers: 2
is the center and r is the radius.![x^2+y^2+8x-16y+31=0\\\left [ x^2+2(4)x+4^2 \right ]+\left [ y^2-2(8)y+8^2 \right ]+31=4^2+8^2](/tpl/images/0653/7591/8b6fc.png)
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A certain circle can be represented by the following equation. x^2+y^2+8x-16y+31=0x 2 +y 2 +8x−16y+3...
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