The square of a number is equal to 10 less than 7 times that number. What are two possible solutions

y=2 or 5

Step-by-step explanation:

let the number be y

y^2=7y-10

y^2-7y+10=0

y^2-2y-5y+10=0

y(y-2)-5(y-2)=0

(y-2)(y-5)=0

y-2=0 y-5=0

y=2 y=5

b

step-by-step explanation:

b