David's company reimburses his expenses on food, lodging, and conveyance during business trips. the company pays $60 a day for food and lodging and $0.65 for each mile traveled. david drove 600 miles and was reimbursed $3,390. part a: create an equation that will determine the number of days x on the trip. (3 points) part b: solve this equation justifying each step with an algebraic property of equality. (6 points) part c: how many days did david spend on this trip? (1 point)

David's company reimburses his expenses on food, lodging, and conveyance during business trips. The company pays $60 a day for food and lodging and $0.65 for each mile traveled. David drove 600 miles and was reimbursed $3,390.

Part A: Create an equation that will determine the number of days x on the trip (3 points)

Each day for x days $60 is spent on food and lodgings, that is a total of 60x dollars

The company pays 65c for each of 600miles  that is

=  

Part B: Solve this equation justifying each step with an algebraic property of equality

Subtract 390 from both sides

Part C = 50 days 

answer: add the !

step-by-step explanation: then we will answer

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."